THỨ TƯ,NGÀY 22 THÁNG 4, 2020

Chem – College: Matchmaking Ranging from Acid and you will Legs Equilirium Constants (Ka and you will Kb)

Bởi Nguyễn Phùng Khuân

Cập nhật: 21/10/2022, 06:38

Chem – College: Matchmaking Ranging from Acid and you will Legs Equilirium Constants (Ka and you will Kb)

When you are given multiple Ka or Kb values (like Ka step 1 , Ka dos , Ka 3 ), you can also combine them together into an overall Ka or Kb by multiplying them together. The equations below display what I mean.

If Mg(OH) 2 has a Kb 1 of 0.3 and a Kb 2 of 4.5 * 10 -3 what is the over all Kb value?

In the event that Be(OH)

If H 3 PO 4 has a Ka 1 of 2.8 * 10 -3 and a Ka 2 of 7.1 * 10 -6 . 3 if the overall Ka is 7.75 * 10 -17 ?

Answer: ( 2.8 * 10 -3 ) * ( 7.1 * 10 -6 ) * Ka 3 = 7.75 * 10 -17

If Al(OH) 3 has a Kb 1 of 0.04 and a Kb 2 of 5.1 * 10 -4 what is the over all Kb value?

If H 2 SO 4 has a Ka 1 of 15 and a Ka 2 of 2.0 * 10 -2 . Then what is the over all Ka value?

If H 3 PO 3 has Ka 2 of 4.7 * 10 -5 and a Ka 3 of 2.3 * 10 -8 . 1 if the overall Ka is 5.5 * 10 -16 ?

Answer: Ka1 * (4.7 * 10 -5 ) * (2.3 * 10 -8 ) = 5.5 * 10 -16 — Ka1 = 5.09 * 10 -4

2 has a Kb 1 of 3.6 * 10 -4 and an overall Kb of 8.2 * 10 -12 what would be the Kb 2 ?

Answer: (3.6 * 10 -4 ) * Kb 2 = 8.2 * 10 -12 — Kb 2 = 2.24 * 10 -8

As it happens one to Ka and you can Kb are regarding you to other inside an algorithm. Which algorithm makes you transfer off Ka in order to Kb and you may vise versa. Brand new algorithm was found lower than .

The fantastic thing about it algorithm is it together with gives you in order to expect if anything is an acidic otherwise a base . How you can figure whether some thing are an acidic or foot by just the Ka otherwise Kb value is to contrast they with the harmony constant for water such as the newest equation less than.

In case the Ka transforms planning to be a larger count than just the brand new Kb then the chemicals will be an acid.

In the event your Kb converts about to getting more substantial matter than just the fresh Ka then your chemicals is a bottom.

Supply the Kb and you can tell if the chemical was an acidic or base whether or not it enjoys an excellent Ka from dos.cuatro * 10 -six .

Answer: Acidic (Ka is actually larger than Kb), Kb = ten -fourteen / dos.cuatro * 10 -six = cuatro.17 * 10 -9

Allow the Ka and give perhaps the agents is actually an acidic otherwise foot whether it provides a good Kb out-of step three.5 * 10 -cuatro .

Answer: Legs (Kb is actually bigger than Ka), Ka = ten -14 / step three.5 * ten -4 = dos.86 * 10 -eleven

Give the Kb and you will give if the agents is an acidic otherwise legs in the event it have good Ka regarding cuatro.step three * ten -9 .

Answer: Feet (Kb is larger than Ka), Kb = ten -14 / 4.step three * ten -9 = 2.thirty two * ten -six

Allow the Ka and you may give whether the chemicals is an acid otherwise base if it keeps an effective Kb out-of 8.9 * 10 -11 .

Answer: Acidic (Ka was bigger than Kb), Ka = 10 -14 / 8.nine * ten -eleven = 1.several * 10 -cuatro

Give the Kb and you will share with whether the toxins was an acidic otherwise foot if this provides a great Ka away from seven.2 * 10 -nine .

Answer: Ft (Kb is actually larger than Ka), Kb = ten -14 / seven.2 * ten -nine = 1.38 * ten -6

Supply the Ka and you can share with whether or not the chemical compounds are an acidic otherwise legs if it has actually an excellent Kb off cuatro.dos * 10 -12 .

Answer: Acidic (Ka are bigger than Kb), Ka = ten -fourteen / 4.dos * ten -eleven = 2.38 * ten -cuatro

Supply the Kb and you can share with whether or not the chemical compounds was an acidic otherwise foot in the event it enjoys a Ka from 3.cuatro * ten -step 3 .

Then what would end up being the Ka

Answer: Acidic (Ka was larger than Kb), Kb = ten -14 / step 3.cuatro * https://datingranking.net/cs/mate1-recenze/ 10 -3 = 2.94 * ten -several

Give the Ka and you will share with whether the agents are an acidic or feet in the event it keeps an excellent Kb of five.6 * ten -eight .

Answer: Ft (Kb is bigger than Ka), Ka = 10 -fourteen / 5.6 * ten -eight = 1.78 * ten -8

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